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Precalculus: An Investigation of Functions, by David Lippman and Melonie Rasmussen, licensed under CC BY-SA 4.0. Read the original free This shelf’s study material is shared under the same license (CC BY-SA 4.0).
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Chapter 2 · pp. 6–6
About the Second Edition
This chapter pulls together several core precalculus ideas: how to find and use zeros of polynomials, how rational functions behave for large inputs, how vectors combine through the dot product, how conic sections arise, and how trigonometry links triangles to the unit circle. Each idea comes with a short example so you can try the reasoning yourself.
Polynomial division and the factor theorem
Polynomial long division works like long division with numbers. You repeatedly remove the highest-degree term of what is left. The steps are:
Divide the leading term of the dividend by the leading term of the divisor.
Multiply the whole divisor by that result.
Subtract this product from the dividend.
Repeat with the new remainder until its degree is lower than the divisor's degree.
Example: (x2+3x+2)÷(x+1). Dividing x2 by x gives x. Multiply: x(x+1)=x2+x. Subtract to get 2x+2. Dividing 2x by x gives +2. Multiply: 2(x+1)=2x+2. Subtract to get 0. The quotient is x+2 with remainder 0.
The factor theorem says that x−c is a factor of a polynomial p(x) exactly when p(c)=0. The reason is that if p(c)=0, dividing p(x) by x−c leaves remainder 0, so the division is exact. Example: for p(x)=x2−5x+6, we get p(2)=4−10+6=0. So x−2 is a factor, and indeed p(x)=(x−2)(x−3).
The two ideas work together. Once you find a zero c, you can divide by x−c to get a simpler polynomial and keep going.
Finding zeros
The rational roots theorem gives a finite list of candidates. If a polynomial has integer coefficients, any rational zero has the form qp, where p divides the constant term and q divides the leading coefficient.
Example: for 2x2+x−3, p is among ±1,±3 and q is among ±1,±2. The candidates are ±1,±3,±21,±23. Testing shows that x=1 is a zero, since 2+1−3=0.
Common mistake: thinking the theorem finds every zero. It only lists possible rational zeros, and each one must still be tested. Irrational and nonreal zeros are never on the list. For x2−2, the candidates are ±1,±2, and none works. Its zeros are ±2.
Conjugate pairs. If a polynomial has real coefficients and a+bi is a zero with b=0, then a−bi is also a zero. Nonreal zeros come in pairs. For example, x2+1 has zeros i and −i. A consequence: since nonreal zeros pair up, an odd-degree polynomial with real coefficients must have at least one real zero.
Oblique asymptotes of rational functions
A rational function has an oblique (slant) asymptote when the degree of the numerator is exactly one more than the degree of the denominator. Dividing the numerator by the denominator gives a linear quotient plus a remainder term. That remainder term shrinks toward 0 when ∣x∣ is large, so the graph gets close to the line given by the quotient.
Example: f(x)=xx2+1=x+x1. As ∣x∣ grows, x1 approaches 0, so the graph approaches the line y=x. Polynomial long division is the tool you use to find the line when the division is not as easy to see.
The dot product
The dot product of vectors a and b is
a⋅b=a1b1+a2b2=∣a∣∣b∣cosθ,
where θ is the angle between the vectors. The component form is easy to compute. The cosine form connects the result to the angle.
Example: ⟨1,2⟩⋅⟨3,−1⟩=(1)(3)+(2)(−1)=1.
If the dot product is 0, then cosθ=0 (for nonzero vectors), so the vectors are perpendicular. You can also solve the cosine form for cosθ to find the angle between two vectors.
Common mistake: believing that the dot product is a vector. It is a single number (a scalar), found by multiplying matching components and adding the products. For example, ⟨2,0⟩⋅⟨0,5⟩=0, which is a number, not a vector. (It is 0 because these vectors are perpendicular.)
Conic sections
Conic sections are the curves formed when a plane slices a double cone. The four types are the circle, ellipse, parabola, and hyperbola. The angle of the slice decides which curve you get:
A slice perpendicular to the cone's axis gives a circle.
A tilted slice that cuts through one nappe (one half of the cone) gives an ellipse.
A slice parallel to the cone's side gives a parabola.
A steep slice that cuts both nappes gives a hyperbola.
Right triangles and the unit circle
Right-triangle trigonometry and unit circle trigonometry describe the same functions. On the unit circle, the point at angle θ has coordinates (cosθ,sinθ). So cosθ is the x-coordinate and sinθ is the y-coordinate.
For an acute angle, picture a right triangle with hypotenuse 1 inside the unit circle. Its legs have lengths cosθ and sinθ. This matches the ratios adjacent/hypotenuse and opposite/hypotenuse, because dividing by a hypotenuse of 1 changes nothing.
The unit circle goes further. It lets you define the functions for angles beyond 90∘, where no right triangle contains the angle. Example: sin150∘=21, the y-coordinate of the point at 150∘.
Check yourself
Use the factor theorem to decide whether x+1 is a factor of x2+4x+3.
List all possible rational zeros of 3x2+2x−5. Then find which one is actually a zero.
A polynomial with real coefficients has 2−3i as a zero. What other zero must it have?
What is the slant asymptote of f(x)=xx2+2x? Why does a slant asymptote exist here?
Compute ⟨4,3⟩⋅⟨−3,4⟩. What does the result tell you about the two vectors?